In my July 1, 2011 posting entitled

**, I introduced you to an alternate method for adding fractions called***Fractions for the Confused and Bewildered***Cross Over**, but sometimes students may have to add more than two fractions. What happens then? Let’s suppose we have the following problem.Start out by multiplying the numerator of the first fraction by the denominators of the other two fractions as shown above.

**(1 × 5 × 3 = 15)**

Do the exact same thing with the second fraction and then add that product to the first.

Now repeat this process using the last numerator of

**2**and add that to**33**.
The result is the numerator of the answer. To find the denominator, just multiply all
the denominators together just as we do in the

**Cross Over**strategy.
As usual, you may need to reduce to
lowest terms or change an improper fraction to a mixed number. In this example, the improper fraction becomes
a mixed number.

For many of us, this may seem like a
lengthy and complicated process but for my mathphobic students who have
difficulty finding the lowest common denominator, they view this as easy and
stress free. The key is that they have a
strategy that works for them.

If you are interested in other alternate ways to teach fractions, check out the resource

**Fractions for the Confused and Bewildered.**
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